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simcacl August 21, 2012 - 16:37
Posts: 9
 Joined: 2012-08-19
 Location: Italy

I have a supposed simple question:I using Igor 6.22 and I want use the OR operator || .
I understood that ther eis some problem related to the compatibility mode bu I don't really get the point

I changed the # pragma to
#pragma rtGlobals=2
but I doesnt work?

How can I write the simple statment:

if (( a==0) || (b==0))

Have I to write Silent 101 somewhere???
Thanks
jtigor August 21, 2012 - 17:28
Posts: 180
 Joined: 2007-09-04
 Location: United States

With either #pragma rtGlobals=1 or 2, and Igor6.23, the following works for me

function junk(a, b)
	variable a, b
	if( (a == 0) || (b == 0))
		print a, b
	endif
end

Executing junk(1,0) command line, results in: 1 0

How is your code failing? Any error messages? Try inserting print statements (or use the debug window) to see how your code is flowing.
hrodstein
 August 21, 2012 - 18:18
Posts: 911
 Joined: 2007-06-21
 Location: United States

Compatibility mode applies to experiments created in Igor Pro 3 or earlier so unless you have ancient experiments you can ignore it.

For details:

DisplayHelpTopic "Old-Style Comments and Compatibility Mode"
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