Changing the bottom axis for waterfall diagram
| March 8, 2010 - 09:27 | |||
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If your graph is truly a waterfall plot (made using Windows->New->Packages->Waterfall Plot) then you have just one X wave. You can change the X wave to another using ReplaceWave/X trace=intensity, vector If your waterfall plot is just a graph with lots of traces, use this function: Function ReplaceAllXWavesInGraph(graph, newXWave) String graph Wave newXWave if (strlen(graph) == 0) graph = WinName(0,1) endif String tlist = TraceNameList(graph, ";", 1) Variable i Variable ntraces = ItemsInList(tlist) for (i = 0; i < ntraces; i += 1) String oneTrace = StringFromList(i, tlist) ReplaceWave/X/W=$graph trace=$oneTrace, newXWave endfor end Note that this function is really basic- it has no error checking, and it replaces the X wave for *all* traces in the graph regardless. It does, however, allow you to use "" as the name of the graph in order to work on the top graph window. John Weeks |
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Joined: 2009-09-14
Location: Australia
Hi everyone
I have a waterfall diagram, which displays a set of graphs of 'intensity' vs 'theta',
such that the bottom axis represents the unit in theta, θ.
Normally, if I have two waves named 'intensity' and 'theta',
then I can replace 'theta' with another wave called 'vector', Q.
Since Q is related to θ by:
Q = 4*pi/lamba*sin(θ*pi/180)
, then with this command
, a new graph can be displayed for 'intensity' vs 'vector'.
But as a waterfall diagram is a combination of many waves, so is there a quick way to change the unit of the bottom axis from θ to Q instead of executing the command many times for all the individual waves and re-plot the waterfall again?
Thanks for any help!