Elliptic integrals
amtravco
Sat, 04/18/2020 - 03:09 pm
It would be nice to have complete and incomplete elliptic integrals of the first and second kind available.
Sat, 04/18/2020 - 03:09 pm
It would be nice to have complete and incomplete elliptic integrals of the first and second kind available.
OK, I've figured out that
E(k) = (pi/2)*hyperG2F1(-1/2, 1/2, 1, k^2)
and
K(k) = (pi/2)*hyperG2F1(1/2, 1/2, 1, k^2).
Maybe not the most efficient implementation, but it will do the job.
April 18, 2020 at 06:29 pm - Permalink